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28 August, 17:52

Russel throws a soda from the balcony of his house to his friend Jones in the pool. If the soda is released 20 feet from the ground, and is thrown with a downward velocity of 2 ft/s, how long till the soda hits the pool, ignoring air resitance? Use the formula, where h is the height of the soda in feet and t is the time in seconds since Russel threw it. Round your answer to the nearest tenth.

A. 0.5 seconds B. 0.8 seconds C. 1.1 second D. 1.6 seconds

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  1. 28 August, 18:09
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    Using the formula S = ut + 1/2at²

    S=h = 20ft, u = 2ft/s, and a = 10m/s²

    Thus; 20 = 2t + 20t²

    Therefore; 20t²+2t-20=0

    Solving the equation quadratically for the value of t,

    we get; t = 1.057 or t=-1.182

    But t can not be negative,

    Therefore, t = 1.1 seconds (to the nearest tenth)
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