Russel throws a soda from the balcony of his house to his friend Jones in the pool. If the soda is released 20 feet from the ground, and is thrown with a downward velocity of 2 ft/s, how long till the soda hits the pool, ignoring air resitance? Use the formula, where h is the height of the soda in feet and t is the time in seconds since Russel threw it. Round your answer to the nearest tenth.

A. 0.5 seconds B. 0.8 seconds C. 1.1 second D. 1.6 seconds

Question

Matias Hays

Mathematics

28 August, 17:52

Russel throws a soda from the balcony of his house to his friend Jones in the pool. If the soda is released 20 feet from the ground, and is thrown with a downward velocity of 2 ft/s, how long till the soda hits the pool, ignoring air resitance? Use the formula, where h is the height of the soda in feet and t is the time in seconds since Russel threw it. Round your answer to the nearest tenth.

A. 0.5 seconds B. 0.8 seconds C. 1.1 second D. 1.6 seconds

+5

Answers (1)

Know the Answer?

Lilly Hoover · Answer 1

Using the formula S = ut + 1/2at²

S=h = 20ft, u = 2ft/s, and a = 10m/s²

Thus; 20 = 2t + 20t²

Therefore; 20t²+2t-20=0

Solving the equation quadratically for the value of t,

we get; t = 1.057 or t=-1.182

But t can not be negative,

Therefore, t = 1.1 seconds (to the nearest tenth)