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25 September, 05:24

What is the axis of symmetry and vertex given the equation,

y=2x^2-12x+21

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  1. 25 September, 05:49
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    y = 2x² - 12x + 21 = 2 (x² + 6x) + 21.

    Using the complet the square method, you get:

    2 (x² + 6x) + 21 = 2 (x² + 6x + 9) - 2*9 + 21 = 2 (x + 3) ² + 3.

    So the axis of symmetry is: x = - 3.

    The vertex is: (-3, 3)
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