If a right triangle has a leg that measures 24 and a hypotenuse that measures 25. what is the length of the other leg?

Phytagoras' Theorem states that in any right triangle, the square of the hypotenuse is equal to the sum of the squares of the two legs. If c represents the hypotenuse, a and b represent the two leg, the theorem could be written as below.

c² = a² + b²

a² + b² = c

From the question, we could get information that

c = 25

a = 24

and we should find the value of b

Plug in the numbers to the formula

a² + b² = c²

24² + b² = 25²

576 + b² = 625

b² = 625 - 576

b² = 49

b = √49

b = 7

The length of the other leg is 7

Hypotenuse ^2 = leg1 ^2 + leg2 ^2

25^2 = 24^2 + leg2 ^2

leg2 ^2 = 25^2-24^2 = 625 - 576=49

⇒ leg = V49

⇒ leg = 7