Katy chose a card at random from a deck of 52 cards. Katy replaced the first card and then chose a second card. What is the probability that Katy chose a diamond both times?

A). 1/16

B). 1/52

C). 1/169

D). 1/208

Question

Axel Sims

Mathematics

18 April, 05:38

Katy chose a card at random from a deck of 52 cards. Katy replaced the first card and then chose a second card. What is the probability that Katy chose a diamond both times?

A). 1/16

B). 1/52

C). 1/169

D). 1/208

+4

Answers (2)

Know the Answer?

Jaqueline Serrano · Answer 1

52 total cards ... 13 total diamonds in the deck

P (1st card picked being a diamond) = 13/52

replacing the card, so the sample space remains the same

P (2nd card being a diamond) = 13/52

P (both) = 13/52 * 13/52 = 169/2704 = 1/16 <==

Cali Page · Answer 2

Any suit is a quarter of the deck, or 13 cards out of 52, so with replacement the probability of picking two straight of any suit is the same.

P (DD) = (1/4) (1/4)

P (DD) = 1/16

Katy chose a card at random from a deck of 52 cards. Katy replaced the first card and then chose a second card. What is the probability that Katy chose a diamond both times?A). 1/16B). 1/52C). 1/169D). 1/208

Katy chose a card at random from a deck of 52 cards. Katy replaced the first card and then chose a second card. What is the probability that Katy chose a diamond both times?

A). 1/16

B). 1/52

C). 1/169

D). 1/208