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15 March, 14:57

What is the remainder when (x3 - 6x2 - 42x + 79) is divided by (x + 5) ?

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  1. 15 March, 15:06
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    We can do synthetic division to solve this or just normal division. Either way, the remainder would be:

    -406 / (x+5)

    The whole result is this:

    (x3 - 6x2 - 42x + 79) / (x+5) = x2 - 11x + 97 - 406 / (x+5)

    With the remainder as - 406 / (x+5)
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