A student is standing 20 feet away from the base of a tree. He looks to the top of a tree at a 50 degree angle of elevation. His eyes are 5 feet above the ground. Using cos 50 degrees is about 0.64 what is the height of the treetops the nearest foot?

Question

Guest

Mathematics

17 November, 19:16

A student is standing 20 feet away from the base of a tree. He looks to the top of a tree at a 50 degree angle of elevation. His eyes are 5 feet above the ground. Using cos 50 degrees is about 0.64 what is the height of the treetops the nearest foot?

+4

Answers (2)

Know the Answer?

Lizeth Curtis · Answer 1

Lizeth Curtis 17 November, 19:22

0

The answer is 29 fett

Kadin Gallagher · Answer 2

This is the concept of application of trigonometry. The height of the tree will be found as follows;

tan theta=[opposite]/[adjacent]

theta=50

opposite=height of the tree = (h+5)

adjacent=distance of the student from the tree

Thus:

tan 50 = (h+5) / 20

h+5=20tan50

h=5+20tan50

h=5+23.84

h=28.84

Therefore the height of the tree was:

28.84+5

=33.84