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25 August, 01:40

The Peimeter of a rectangle is 56 M if the width were doubled and the length were increased by 8 M, then the perimeter would be 82m. What are the dimensions?

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  1. 25 August, 01:49
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    l + w + l + w = 56

    2l + 2w = 56

    2w = 56 - 2l

    (2w) + (2w) + (l + 8) + (l + 8) = 82

    2 (2w) + 2 (l + 8) = 82

    2 (56 - 2l) + 2l + 16 = 82

    112 - 4l + 2l + 16 = 82

    112 - 82 + 16 = 4l - 2l

    46 = 2l

    46/2 = l

    23 = l

    2w = 56 - 2l

    2w = 56 - 2 (23)

    2w = 56 - 46

    2w = 10

    w = 10/2

    w = 2

    length (l) = 23 m and width (w) = 2 m
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