Two passenger trains traveling in opposite directions meet and pass each other. Each train is 1/12 miles long and is traveling 50 mph. How many seconds after the front cars of the trains meet will their rear cars pass each other?

6 seconds

Step-by-step explanation:

1/12 mile * 5280 feet/mile = 440 feet per train

50 miles/hour * 1/3600 hr/sec * 5280 ft/mile = 73 1/3 ft/second

one train has to travel 440 feet to pass the other train

440 feet * 1 / (73 1/3) sec/ft = 6 seconds