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26 January, 16:58

Solve the following systems using substitution.

X - 9y = 25

6x - 5y = 3

+3
Answers (1)
  1. 26 January, 17:03
    0
    x = - 2, y = - 3

    Step-by-step explanation:

    Multiply eqn1 by the LCM of 1 and 6 i. e coefficients of x

    We get:

    6x - 54y = 150 (eqn1)

    6x - 5y = 3 (eqn2)

    - 49y = 147

    y = 147

    -49

    y = - 3

    Substitute y in eqn2

    6x - 5 (-3) = 3

    6x + 15 = 3

    6x = - 12

    x = - 2
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