Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile and others are not marked. The probabilities are displayed in the table below:

| Red |Green |Brown

Smile |0.100 |.300 |.10

No smile |0.200 |.150 |.15

If a random candy is chosen from this bag, what is the probability that the candy was red or had no smile?

The correct answer is:

A: 0.60

| Red |Green | Brown Total

Smile |0.100 |.300 |.10 0.50

No smile |0.200 |.150 |.15 0.50

Total 0.30 0.45 0.25 1.00

The probability of choosing red candy is 0.10

The probability of choosing no smile candy is 0.50

The probability of choosing red or no smile = 0.10 + 0.50 = 0.60

I did not use 0.30 as the probability of red because it included the no smile candy. It should only be red candy that has a smile.