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Parker Price
Mathematics
30 April, 14:55
Given that cosθ 1/3 and θ is acute, what is tanθ?
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Aden Lin
30 April, 15:15
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tanθ=2√2
Step-by-step explanation:
cosθ = 1/3, and θ is acute;
cos²θ=1/9
sin²θ+cos²θ=1
sin²θ=1-cos²θ=1-1/9=8/9
=> sinθ=√ (8/9) = 2√2 / 3
tanθ=sinθ/cosθ
tanθ = (2√2 / 3) / (1/3) = 2√2
tanθ=2√2
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