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Kaya Blackwell
Mathematics
25 November, 16:04
What is the product of (3y^-4) (2y^-4) ?
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Shawn Dickson
25 November, 16:07
0
(3y^-4) (2y^-4)
Multiply coefficients
= 6y^-4
Y stays the same
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Damien Montoya
25 November, 16:27
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(x^a) (x^b) = x^ (a+b)
(ab) (cd) = (a) (b) (c) (d)
x^-m=1 / (x^m)
(3y^-4) (2y^-4) =
(3) (y^-4) (2) (y^-4) =
(6) (y^-8) =
6 / (y^8)
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