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15 April, 08:54

What is the vertex of f (x) = | 8x + 8| - 3?

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  1. 15 April, 09:04
    0
    (-1, - 3)

    Step-by-step explanation:

    Vertex of y = |x| have the coordinates (0, 0).

    f (x) + n - shift the graph n units up

    f (x) - n - shift the graph n units down

    f (x + n) - shift the graph n units to the left

    f (x - n) - shift the graph n units to the right

    nf (x) - stretches/shrinks vertically

    f (nx) - stretches/shrinks horizontally

    We have

    f (x) = |8x + 8| - 3 = |8 (x + 1) | - 3 = |8| · |x+1| - 3 = 8|x + 1| - 3

    g (x) = |x| → f (x) = 8g (x + 1) - 3

    vertically streched by 8 (0, 8 · 0) → (0, 0)

    shifted 1 unit to the left (0 - 1, 0) → (-1, 0)

    shifted 3 units down (-1, 0 - 3) → (-1, - 3)
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