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3 July, 22:30

The manager of a gas station has observed that the times required by drivers to fill their car's tank and pay are quite variable. In fact, the times are exponentially distributed with a mean of 7.5 minutes. What is the probability that a car can complete the transaction in less than 5 minutes?

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  1. 3 July, 22:50
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    Answer: 0.49

    Step-by-step explanation:

    The mean = E[x]=1/l = 7.5 min

    l=1/7.5 = 10/75=2/15

    The exponential distribution's probability density function is looking like that:

    F (x) = l*e^ (-l*x) = 2/15*e^ (-2*x/15)

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