Ask Question
30 December, 11:07

If x+y+z=13 what is the value of (x-1) + (y+1) + (z-1)

+2
Answers (1)
  1. 30 December, 11:13
    0
    12

    Step-by-step explanation:

    (x-1) + (y+1) + (z-1)

    = x - 1 + y + 1 + z - 1

    = x + y + z - 1

    = (x + y + z) - 1

    given that x+y+z = 13, substitute this value into the equation aove

    (x + y + z) - 1

    = 13 - 1

    = 12
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If x+y+z=13 what is the value of (x-1) + (y+1) + (z-1) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers