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23 July, 23:17

A particle's position is given by x = 4.0t^2 - 32t + 36, with x in meters and time t in seconds. At what position does the particle come to a momentary stop, to reverse its motion?

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  1. 23 July, 23:41
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    When it gets to zero or the intercept

    factor

    x=4 (t^2-8t+9)

    x = (4) (t-9) (t+1)

    set to zero

    t-9=0

    t=9

    t+1=0

    t=-1, false, time cannot be negative

    at t=9 seconds
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