A particle's position is given by x = 4.0t^2 - 32t + 36, with x in meters and time t in seconds. At what position does the particle come to a momentary stop, to reverse its motion?

Question

Tristan Tanner

Mathematics

23 July, 23:17

A particle's position is given by x = 4.0t^2 - 32t + 36, with x in meters and time t in seconds. At what position does the particle come to a momentary stop, to reverse its motion?

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Answers (1)

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Isaias Greene · Answer 1

When it gets to zero or the intercept

factor

x=4 (t^2-8t+9)

x = (4) (t-9) (t+1)

set to zero

t-9=0

t=9

t+1=0

t=-1, false, time cannot be negative

at t=9 seconds