How many real solutions are there to 5x^2+6x+4=0?

No real solutions

Step-by-step explanation:

Use the discriminant to determine the number of real solutions to a quadratic equation.

The general form for a quadratic equation is ax² + bx + c

The discriminant is b² - 4ac

The following 3 rules apply ...

1. If b² - 4ac > 0, then there are 2 real solutions

2. If b² - 4ac = 0, then there is one real solution

3. If b² - 4ac < 0 then there are no real solutions

For this problem,

a = 5

b = 6

c = 4

Plug them into b² - 4ac ...

6² - 4 (5) (4)

36 - 80

-54 so b² - 4ac < 0, there are no real solutions