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11 August, 20:55

How do I calculate the abs of value of (2-3i) ^2

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  1. 11 August, 20:59
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    (2-3i) (2-3i)

    Foil this out.

    4-12i+9i²

    = 4-12i-9

    Keep in mind i² = - 1.

    = - 5-12i
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