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21 March, 18:31

Solve the inequality.

4x + 1 < 8x - 3 < 4x + 5

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Answers (1)
  1. 21 March, 18:34
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    1
    Step-by-step explanation:

    4x + 1 < 8x - 3 < 4x + 5

    Split into two inequalities

    4x + 1 < 8x - 3 and 8x - 3 < 4x + 5

    Do the first one first

    4x + 1 < 8x - 3

    Subtract 4x from each side

    4x - 4x + 1 < 8x-4x - 3

    1 < 4x-3

    Add 3 to each side

    1+3 < 4x-3+3

    4 < 4x

    Divide by 4

    4/4 <4x/4

    1
    Now the other

    8x - 3 < 4x + 5

    Subtract 4x from each side

    8x - 4x-3 < 4x+5-4x

    4x-3 < 5

    Add 3 to each side

    4x-3+3 < 5+3

    4x<8

    Divide by 4

    4x/4 <8/4

    x <2

    Put them back together

    1
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