Ask Question
5 February, 20:43

What is the inradius of a triangle with side lengths 9, 40, and 41?

+3
Answers (1)
  1. 5 February, 21:05
    0
    Answer: 20.5

    Step-by-step explanation:

    From the measure of the length of the sides of the triangle, 9, 40 and 41 we can infer that the triangle is a right angled triangle. 9-40-41 is a Pythagorean triplet.

    In a right angled triangle, the circumradius is half the hypotenuse.

    In the given triangle, the hypotenuse = 41.

    Therefore, the circumradius is 41:2 = 20.5 units.
Know the Answer?