Use substitution to solve the system of equations.

y = 2x + 16

2x - 7y = - 64

A) (-4, 8)

B) (-1, 11)

C) (8, - 4)

D) (-7, - 11)

Step-by-step explanation:

y = 2x + 16 ... equation 1

2x - 7y = - 64 ... equation 2

Now putting y = 2x + 16 in equation 2

2x - 7 (2x + 16) = - 64

2x - 14x - 112 = - 64

-12x = - 64+112

-12x = 48

Therefore x = - 4

Now putting x = - 4 in equation 1

y = 2 * (-4) + 16

= - 8 + 16

= 8

A) (-4, 8)

Step-by-step explanation:

to solve this system of equation

we will say let

y = 2x + 16 ... equation 1

2x - 7y = - 64 ... equation 2

substitute equation 1 into equation 2

2x - 7y = - 64 ... equation 2

2x - 7 (2x + 16) = - 64

2x - 14x - 112 = - 64

combine the like terms

2x - 14x = - 64 + 112

-12x = 48

divide both sides by the coefficient of x

-12x/-12 = 48/-12

x = - 4

put the value of x = - 4 into equation 1

y = 2x + 16 ... equation 1

y = 2 (-4) + 16

y = - 8 + 16

y = 8

therefore the value of x and y is - 4 and 8 respectively