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11 August, 06:15

What are the coordinates of the focus of the conic section shown below?

y^2-4x+4y-4=0

... ?

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  1. 11 August, 06:21
    0
    The answer is

    y^2-4x+4y-4=y^2+4y-4x-4 = (y+2) ²-4x - 8 = 0

    it is the same of x + 2 = (1/4) (y+2) ²

    the main formula is x-h = a (y-k) ² so h=-2, k = - 2 and a=1/4
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