Find the values of the six trigonometric functions of theta based on the following constraints:

1.) Theta is found in quadrant II.

2.) sin theta = 3/5

Hello,

1)

sin x=3/5==>x=126.869897 ... ° (since in quadrant II)

2) = = >cos x<0

cos x=-√ (1-sin ² x) = - √ (1-9/25) = - 4/5

tan x = (3/5) / (-4/5) = - 3/4

cotg x=-4/3 = 1/tan x

sec x=1/cos x=-5/4

cosec x=1/sin x=5/3

The first step to take here is to evaluate the equation sin theta = 3/5. Theta is equal to 36.86 degrees. Since the angle lies in the second quadrant, the angle is 180-36.86 or equal to 143.13 degrees. Thus, sin theta = 3/5cos theta = - 4/5tan theta = - 3/4csc theta = 5/3sec theta = - 5/4cot theta = - 4/3