Regina's work to find the surface area of a square pyramid from its net is shown below.
A square pyramid. The square base has side lengths of 9.4 inches. The triangular sides have a height of 11.9 inches.
Surface area of the pyramid = 4 (one-half (9.4) (12.8)) + 9.4 squared = 329 square inches
What error did Regina make?
She should have used One-half (9.4) (11.9) to represent the area of a single triangle.
She should have multiplied all the terms inside the parentheses by 4 when she simplified.
She should have used One-half (4.7) (12.8) to represent the area of a single triangle.
She should have used a different collection of shapes as the net of the pyramid.
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