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Layton Murray
Mathematics
31 August, 18:45
How to multiply a matrices 3x3 by 3x2
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Noe Mccullough
31 August, 18:54
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The top row of matrix A (1, 2, 1) is multiplied with the first column of matrix B (1,0,-1) and the result is 1x1 + 2x0 + 1x - 1 = 0 this is row 1 column 1 of the resultant matrix
The top row of matrix A (1,2,1) is multiplied with the second column of matrix B (-1, - 1, 1) and the result is 1 x-1 + 2 x - 1 + 1 x 1 = - 2, this is row 1 column 2 of the resultant matrix
Repeat with the second row of matrix A (-1,-1.-2) x (1,0,-1) = 1 this is row 2 column 1 of the resultant matrix, multiply the second row of A (-1,-1,-2) x (-1,-1,1) = 0, this is row 2 column 2 of the resultant
Repeat with the third row of matrix A (-1,1,-2) x (1,0, - 1) = 1, this is row 3 column 1 of the resultant
the third row of A (-1,1,-2) x (-1,-1,1) = - 2, this is row 3 column 2 of the resultant matrix
Matrix AB (0,-2/1,0/1,-2)
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