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Imani Smith
Mathematics
24 October, 09:03
Cos2x - sqrt 2 sinx=1 Find all solutions
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Lena Wagner
24 October, 09:23
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Cos 2 x - √2 sin x = 1
cos² x - sin² x - √2 sin x = 1
1 - 2 sin² x - √2 sin x = 1
- 2 sin² x - √2 sin x = 1 - 1
- 2 sin² x - √2 sin x = 0 / · ( - 1)
2 sin² x + √2 sin x = 0
sin x (2 sin x + √2) = 0
sin x = 0, x 1 = k π, k ∈ Z
or: 2 sin x + √ 2 = 0
2 sin x = - √2
sin x = - √2 / 2
x 2 = 5 π / 4 + 2 kπ, x 3 = 7 π / 4 + 2 kπ, k ∈ Z
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