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17 July, 12:53

Carrots cost 75 cents per kilogram and potatoes cost 70 cents per kilogram. a shopper bought 9 kg of the vegetables for $6.60. how many kilograms of each did the shopper buy?

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Answers (2)
  1. 17 July, 13:04
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    Let us assume that the weight of carrots is "X" kilogram

    Since the total weight is 9 kilograms, the weight of potatoes should be "9-X" kilograms.

    The cost of "X" kilograms of carrot at $0.75/kilogram is calculated as = 0.75*X = 0.75X

    The cost of "9-X" kilograms of potatoes at $0.70/kilogram is calculated as 0.70 * (9-X)

    We know that the total cost is $6.60

    We now frame the equation as:

    0.75X + (9-X) * 0.70 = 6.60

    0.75X + 6.30 - 0.70X = 6.60

    0.05X = 0.30

    X = 0.30/0.05 = 30/5 = 6

    Therefore weight of carrots = 6 Kilograms and

    Weight of potatoes = 9-6 = 3 Kilograms
  2. 17 July, 13:19
    0
    Amount of Carrot bought at $0.75 per kilogram = x

    Amount of potatoes bought at $0.70 per kilogram = y

    Since, a shopper bought 9 kg of the vegetables.

    Therefore, x + y = 9 (equation 1)

    A shopper bought 9 kg of vegetables at $6.60.

    Therefore, 0.75x+0.70y=6.60

    Multiplying the above equation by 100.

    75x+70y=660 (equation 2)

    Multiplying equation 1 by '-75' and adding it to the equation 2, we get

    -75x-75y+75x+70y = 660-675

    -5y = - 15

    y = 3

    x + y = 9

    x + 3 = 9

    x = 9 - 3 = 6

    Therefore, the shopper bought 6kg of carrots and 3 kg of potatoes.
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