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29 August, 02:24

The area of a rectangle is given by A (x) = x2 + 5x with x being the height and x + 5 being the base. If the area is 14, what is the only viable solution for the height? Why are there not two solutions?

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  1. 29 August, 02:44
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    See below.

    Step-by-step explanation:

    A (x) = x^2 + 5x

    A (x) = x^2 + 5x = 14

    x^2 + 5x - 14 = 0

    (x + 7) (x - 2) = 0

    x + 7 = 0 or x - 2 = 7

    x = - 7 or x = 2

    x is the height of a rectangle.

    The only viable solution is x = 2 because the height of a rectangle cannot be a negative number such as - 7.
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