There are 12 brown socks and 6 blue socks in a drawer. In the dark, Jason pulls out a sock and puts it on his right foot. Then he pulls out another sock and puts it on his left foot.

What is the probability that Jason has two brown socks on his feet?

11/27

22/51

4/9

8/17

Question

Ollie

Mathematics

31 December, 15:22

There are 12 brown socks and 6 blue socks in a drawer. In the dark, Jason pulls out a sock and puts it on his right foot. Then he pulls out another sock and puts it on his left foot.

What is the probability that Jason has two brown socks on his feet?

11/27

22/51

4/9

8/17

+3

Answers (1)

Know the Answer?

Lilibeth · Answer 1

22/51

Step-by-step explanation:

The total number of socks is 12+6 = 18 socks

P (1st sock is brown) = brown/total = 12/18 = 2/3

We take one sock that is brown so there are 17 socks 11 brown and 6 blue

P (2nd sock is brown) = brown=total = 11/17

P (1st brow, 2nd brown not replaced) = 2/3 * 11/17

=22/51

There are 12 brown socks and 6 blue socks in a drawer. In the dark, Jason pulls out a sock and puts it on his right foot. Then he pulls out another sock and puts it on his left foot.What is the probability that Jason has two brown socks on his feet?11/2722/514/98/17

There are 12 brown socks and 6 blue socks in a drawer. In the dark, Jason pulls out a sock and puts it on his right foot. Then he pulls out another sock and puts it on his left foot.

What is the probability that Jason has two brown socks on his feet?

11/27

22/51

4/9

8/17