The sum of 4 consecutive integers is 40 what is the third number in this sequence?

Let's represent the numbers by : x, x+1, x+2, x+3

x+x+1+x+2+x+3=40 The third number in the sequence is x+2

4x+6=40 8.5+2=10.5

4x+6-6=40-6 Therefore the third number in the sequence is

4x=34 10.5

4x/4=34/4

x=8.5