What is the solution to this system of equations? {5x+4y=22 3x+4y=10

Multiply 2nd equqation by - 1 and add to first

5x+4y=22

-3x-4y=-10 +

2x+0y=12

2x=12

divide by 2

x=6

sub back

3x+4y=10

3 (6) + 4y=10

18+4y=10

minus 18 both sides

4y=-8

divide by 4

y=-2

(x, y)

(6,-2) is solution