A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? Model the scenario with an equation and solve. Use complete sentences to explain whether or not your solution is reasonable.

Question

Frank Sampson

Mathematics

1 January, 12:36

A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? Model the scenario with an equation and solve. Use complete sentences to explain whether or not your solution is reasonable.

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Answers (1)

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Ernesto Edwards · Answer 1

Let x = amt of 5.50 per lb coffee

then

(200-x) = amt of 3.25 per lb coffee

;

5.50x + 3.25 (200-x) = 4.49 (200)

:

5.5x + 650 - 3.25x = 898

:

5.5x - 3.25x = 898 - 650

:

2.25x = 248

x =

x = 110.222 ~ 110 lb of $5.50 coffee

and

200 - 110.222 = 89.77 ~ 90 lb of $3.25 coffee