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17 September, 12:27

The height of an object above the ground in feet can be modeled as a function of time, t, in seconds using the equation: h (t) = - 16 (t-3) ^2 + 288 for t grater than or equal to 0. a) Find the time in seconds when the object reaches the ground (h=0). Round your answer to the nearest second. Hint - Solve by taking the square root. b) Find all times when the object is at a height of 150 feet. Round your answer to the nearest second. Hint-Solve by taking the square root.)

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  1. 17 September, 12:34
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    (a) t = 7 sec approximately; (b) t = 6 sec

    Step-by-step explanation:

    (a) Set h (t) = - 16 (t-3) ^2 + 288 = 0 and solve for t:

    16 (t-3) ^2 = 288

    After simplification, this becomes (t - 3) ^2 = 18, or t - 3 = ±3√2.

    Because t can be only zero or positive, t = 3 + 3√2 = 7 seconds

    (b) Solve h (t) = - 16 (t-3) ^2 + 288 = 150:

    -16 (t-3) ^2 = - 162

    or (t - 3) ^2 = 10.125, or

    t - 3 = ±3.18, or, finally, t = 6.18 sec (discard t = - 0.18 sec)
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