I am confused on how to solve:

Cot^2 (t) / sin^2 (t) = csc (t) - sin (t)

Question

Guest

Mathematics

13 April, 16:25

I am confused on how to solve:

Cot^2 (t) / sin^2 (t) = csc (t) - sin (t)

+2

Answers (1)

Know the Answer?

Jamya Ruiz · Answer 1

Answer: 90°

Step-by-step explanation:

scs (t) = 1/sint

sint²+cost²=1

cot t = (cost/sint) ²

(cost²/sint²) / Sint²=1/sint-sint

cost²/sint⁴=1/sint-sint

cost²=sint³-sint⁵

Cost²=sint³ (1-sint²)

cost²=sint³cost²

1=sint³

sint=1

arcsin1=90°

Cot^2 (t) = (cost/sint) ²

I am confused on how to solve:Cot^2 (t) / sin^2 (t) = csc (t) - sin (t)

I am confused on how to solve:

Cot^2 (t) / sin^2 (t) = csc (t) - sin (t)