What is the perimeter of a triangle with vertices located at (1,4), (2,7), and (0,5). round to the nearest hundredth?

A. 7.40 units

B. 6.81 units

C. 5.40 units

D. 6.48 units

You can find the length of each side using the "distance" formula, a result of the Pythagorean Theorem:

d^2 = (x2-x1) ^2 + (y2-y1) ^2

d1^2 = (2-1) ^2 + (7-4) ^2

d2^2 = (0-2) ^2 + (5-7) ^2

d3^2 = (0-1) ^2 + (5-4) ^2

d1=√10, d2=√8, and d3=√2

So d1+d2+d3≈7.40 units