What sequence has an nth term of a (n) = 2n+1

3, 5, 7, 9, 11, ...

Step-by-step explanation:

To obtain the first 5 terms in the sequence substitute n = 1, 2, 3, 4, 5 into the n th term formula, that is

a (1) = 2 (1) + 1 = 2 + 1 = 3

a (2) = 2 (2) + 1 = 4 + 1 = 5

a (3) = 2 (3) + 1 = 6 + 1 = 7

a (4) = 2 (4) + 1 = 8 + 1 = 9

a (5) = 2 (5) + 1 = 10 + 1 = 11