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28 November, 11:36

Find a Cubic function with zeros 3, - 4, and 6

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  1. 28 November, 11:47
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    x = 3 x = - 4 x = 6

    x - 3 = 0 x + 4 = 0 x - 6 = 0

    (x - 3) (x + 4) (x - 6) = 0

    (x² + x - 12) (x - 6) = 0 (x - 3) (x + 4) = x² + 4x - 3x - 12 = x² + x - 12

    x³ - 6x² + x² - 6x - 12x + 72 = 0

    x³ - 5x² - 18x + 72 = 0

    Answer: x³ - 5x² - 18x + 72 = 0
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