Find 3 consecutive integers such that the sum of the first and twice the second is 16 more than twice the third

Answer: 18, 19, 20

Step-by-step explanation:

3 consecutive integers = x, y and z

1st number is X

2nd number is Y which is X + 1

3rd number is Z which is X + 2

Write equation

X + 2Y = 16 + 2Z

Replace Y with X + 1 and Z with X + 2

So,

X + 2 (X + 1) = 16 + 2 (X + 2)

Distribute

X + 2X + 2 = 16 + 2X + 4

Combine like terms

3X + 2 = 2X + 20

Solve for X

3X + 2 - 2 - 2X = 20 + 2X - 2X - 2

X = 18 so, Y is 19 and Z is 20