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22 January, 06:57

The sum of three consecutive odd integers is 21. x + (x+2) + (x+4) = 21 x + (x+1) + (x+2) = 21 x + (x+1) + (x+3) = 21 x + (x+3) + (x+5) = 21

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  1. 22 January, 07:15
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    X + (x+2) + (x+4) = 21

    x+x+x+2+4=21

    3x+6=21

    (3x+6) / 3=21/3

    x+2=7

    x=7-2

    x=5

    Answer 5, 7, 9
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