The sum of three consecutive even numbers is 48. what are the smallest of these numbers

The smallest of these numbers is 15

Explanation: Lets create let statements to solve this

Let x = First integer

Let x + 1 = Second integer

Let x + 2 = Third integer

x + x + 1 + x + 2 = 48

3x + 3 = 48

3x = 45

x = 15

Based on this, we know that the three consecutive numbers are 15, 16, 17. Since 15 is the least out the three numbers, the answer would be 25.