Ask Question
1 March, 08:43

If i^2=-1 and (4+2i) (6-ki) = 30, what is the value of k?

+1
Answers (1)
  1. 1 March, 08:54
    0
    I^2 = - 1

    i = √-1

    Substitute the value of i in the equation:

    (4+2i) (6-ki) = 30

    {4 + (2) (√-1) } {6 - k (√-1) } = 30

    (4 + 2√-1) (6 - k√-1) = 30

    24 - 4k√-1 + 12√-1 - 2k (-1) = 30

    24 - 4k√-1 + 12√-1 + 2k = 30

    -4k√-1+12√-1 + 2k - 6 = 0

    -2√-1 (2k - 6) + (2k-6) = 0

    (-2√-1 + 1) (2k-6) = 0

    2k - 6 = 0

    2k = 6

    k = 3

    So, the value of k is 3.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If i^2=-1 and (4+2i) (6-ki) = 30, what is the value of k? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers