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19 March, 07:07

If sec 2A = 1/sin 13A, determine the angle A in degrees.

a. 5°

b. 6°

c. 3°

d. 7°

+2
Answers (1)
  1. 19 March, 07:28
    0
    Sec 2 A = 1 / cos 2 A

    1 / cos 2 A = 1 / sin 13 A

    cos 2 A = sin 13 A

    2 A = 90° - 13 A

    2 A + 13 A = 90°

    15 A = 90°

    A = 90° : 15

    Answer:

    B) A = 6°
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