Consider the Polynomial P (x) = x^3-5x^2-x+5. is (x-5) a factor?

a No, the remainder is 0, so x-5 is not a factor of P (x)

b Yes, the remainder is 0, so x-5 is a factor of P (x)

c Yes, the remainder is - 240, so x-5 is a factor of P (x)

d No, the remainder is - 240, so x-5 is not a factor of P (x)

Question

Marcelo Middleton

Mathematics

24 July, 04:24

Consider the Polynomial P (x) = x^3-5x^2-x+5. is (x-5) a factor?

a No, the remainder is 0, so x-5 is not a factor of P (x)

b Yes, the remainder is 0, so x-5 is a factor of P (x)

c Yes, the remainder is - 240, so x-5 is a factor of P (x)

d No, the remainder is - 240, so x-5 is not a factor of P (x)

+4

Answers (1)

Know the Answer?

Reese Daniel · Answer 1

Option B, Yes, the remainder is 0, so x-5 is a factor of P (x)

Step-by-step explanation:

Step 1: Factor

p (x) = x^3 - 5x^2 - x + 5

p (x) = (x - 5) (x + 1) (x - 1)

Yes, the remainder is 0 so, x-5 is a factor of p (x)

Answer: Option B, Yes, the remainder is 0, so x-5 is a factor of P (x)

Consider the Polynomial P (x) = x^3-5x^2-x+5. is (x-5) a factor?a No, the remainder is 0, so x-5 is not a factor of P (x)b Yes, the remainder is 0, so x-5 is a factor of P (x)c Yes, the remainder is - 240, so x-5 is a factor of P (x)d No, the remainder is - 240, so x-5 is not a factor of P (x)