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22 April, 22:28

Determine the zero of F (x) = x^2+3x-5

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  1. 22 April, 22:32
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    The answer to your question is:

    Step-by-step explanation:

    x² + 3x - 5

    x² + 3x + (3/2) ² = 5 + (3/2) ²

    (x + 3/2) ² = 5 + 9/4

    (x + 3/2) ² = (20 + 9) / 4

    (x + 3/2) ² = 29/4

    x + 3/2 = ±√29 / 2

    x 1 = - 3/2 + √29/2 x2 = - 3/2 - √29/2

    x1 = 1.19 x2 = - 4.19
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