Determine the zero of F (x) = x^2+3x-5

The answer to your question is:

Step-by-step explanation:

x² + 3x - 5

x² + 3x + (3/2) ² = 5 + (3/2) ²

(x + 3/2) ² = 5 + 9/4

(x + 3/2) ² = (20 + 9) / 4

(x + 3/2) ² = 29/4

x + 3/2 = ±√29 / 2

x 1 = - 3/2 + √29/2 x2 = - 3/2 - √29/2

x1 = 1.19 x2 = - 4.19