What is 7 (2+5v) = 3v+14

First you want to distribute the 7 on the left to get:

14+35v = 3v+14.

Next subtract 3v from both sides to get

14+3v=14

Then subtract 14 from both sides

3v=0

Divide both sides by three to get

v=0.

Plugging in v=0 back into the original equation checks our work and proves v=0

14+35 (0) = 3 (0) + 14

14=14