Ask Question
24 July, 02:48

Use a proof by contradiction to prove that the sum of two odd integers is even CM

+1
Answers (1)
  1. 24 July, 02:50
    0
    Sum of two odd integers is always even.

    Step-by-step explanation:

    Let m and n be two odd integers.

    Since m and n are odd they can be written in the form m = 2r + 1 and n = 2s + 1, where r and s are integers.

    Let us suppose that their sum is not even.

    m + n = (2r+1) + (2s + 1)

    = 2r + 2s + 2

    = 2 (r+s+1)

    = 2z

    Thus, the sum of m and n can be written in the form 2z where z is an integer. But this is a contradiction to the fact that their sum is even.

    Hence, our assumption was wrong and the sum of two odd integers is always even.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Use a proof by contradiction to prove that the sum of two odd integers is even CM ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers