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Chad Mayer
Mathematics
22 March, 00:42
Passes through (3,1), perpendicular to y=-3x+2
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Azaria Ritter
22 March, 01:12
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As it is perpendicular to y = - 3x + 2 and the gradient of that is - 3 we know that the gradient of our line must be - 1 / - 3 = 1/3.
Now we have the general equation of a line m = (y-y1) / (x-x1) to which we can substitute our values.
1/3 = (y - 1) / (x - 3)
x - 3 = 3 * (y - 1)
x - 3 = 3y - 3
x = 3y
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