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8 September, 05:20

given sin θ = - 1/2 and angle θ is in quadrant IV, what is the exact value of cos θ in its simplest form

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  1. 8 September, 05:38
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    Cos θ = √3 / 2.

    Step-by-step explanation:

    The cosine si positive in quadrant IV.

    Using the identity cos θ = √ (1 - sin^2 θ):

    cos θ = √ (1 - (-1/2) ^2)

    = √ (3/4)

    = √3 / 2
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