Mr cruz cut three pieces of wood for a project. The first piece of lumber is the longest. The second is 7/8 times as long as the first piece. the third piece is 12 5/16 inches shorter than the second piece the their piece is 24 7/16 inches long

A) How long is the first piece of wood?

B) How much wood did Mr cruz use to make all 3 pieces?

c) Mr cruz has 32 ft of lumber left he wants to cut 4 more of each of the pieces described above does he have enough lumber? justify your answer

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Mathematics

6 June, 18:47

Mr cruz cut three pieces of wood for a project. The first piece of lumber is the longest. The second is 7/8 times as long as the first piece. the third piece is 12 5/16 inches shorter than the second piece the their piece is 24 7/16 inches long

A) How long is the first piece of wood?

B) How much wood did Mr cruz use to make all 3 pieces?

c) Mr cruz has 32 ft of lumber left he wants to cut 4 more of each of the pieces described above does he have enough lumber? justify your answer

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Answers (1)

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Chance Mendoza · Answer 1

1st piece is the longest

2nd piece is 24 7/16 + 12 5 / 16 = 36 3/4 inches long

3rd piece is 24 7/16 inches

2nd piece is 7/8 as long as first piece so divide the length of the 2nd piece by 7/8

3 3/4 / 7/8 = 42 inches

A) 1st piece is 42" long

B) now add them all: 42 + 36 3/4 + 24 7/16 = 103 3/16 inches total

C) 103 3/16 inches / 12 = 8.6 feet

8.6 x 4 = 34.4 feet, he has 32 feet so he does not have enough to cut 4 more of each size.