Mathematics

15 April, 03:44

The opposite angles of a quadrilateral inscribed in a

circle are supplementary:

mZQ + m2S 180°

mZS = 180° - mZQ = 180° - 68° = 112°

mZR + m2T = 180°

(3x + 40) + (5x - 52) = 180°

Solving for x, x = 24.

Substituting the value of x in the expressions for mZR and

mZT, mZR = 112º and mZT = 68°. Enter the correct answer.

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